Solve quadratic equations

Factor or use the formula, then find every solution.

Algebra: Factoring and quadratics

If a product equals 0, one of its factors must be 0. When factoring is hard, use the quadratic formula.

x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

Work through it

$(x - 2) (x - 3) = 0$

$x = 2$ or $x = 3$

$a = 1, b = - 4, c = 1$

$x = \frac{4 \pm 12}{2} = 2 \pm 3$

$x^{2} = 9$ , so $x = 3$ .

There are two solutions: $x = 3$ and $x = - 3$ .

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